Good morning,
thank you for your fastr reply. I answer to your request below:

First please let me clarify what you are doing, because it is not fully clear to me, and ask some additional questions.

1. So, in your program, you first execute the 2nd part you listed (with the EasyUAClient), and then you execute the 1st part (with Process.Start), right?

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Yes. This is the sequence

2. Which QuickOPC version are you using?

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I'm using the installation "OPC Labs QuickOPC 2019.2"

3. Do I understand it correctly the "Process.Start" is supposed to start some other program which is not related to&does not have QuickOPC in it? Or is this other program that uses QuickOPC?
----"Process.Start" is called by my program. If it runs before istancing the EasyUAClient it will properly work; if I run "Process.Start" after istancing, it will bring about the program closing.

4. Have you tried enclosing the Process.Start in try/catch, and see if it throws an exception?
----For sure, but the error is not intercepted by using this statement.

Best regards

Good morning,
in my application I properly run a "URL" path with success with this code:

Process.Start(new ProcessStartInfo(e.Uri.AbsoluteUri) { UseShellExecute = true });

After creating a connection with OPCUA server by istancing the EasyClient,
the same code above stops to work and closes suddenly the application (WPF with NET.framework 4..
It happens even after destroying all the OPCUA references.

Please, be so kind to inform me about some ideas.
Tks a lot and best regards

This is the code I use to istance the OPCUA server

private EasyUAClient _Client = null;
private UADiscoveryElementCollection _EndPoint = null;
private UAEndpointDescriptor _endPointDescriptor = null;

if (_Client == null)
_Client = new EasyUAClient();

string uriAdress = (@"opc.tcp://" + _cfgManager.ApplSettings.ServerURI + ":" + _cfgManager.ApplSettings.ServerPort.ToString()).Trim();

_endPointDescriptor = uriAdress;

_EndPoint = _Client.DiscoverLocalEndpoints(uriAdress);